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# grade 8 mathematics

ABCD is square of side 6 cm. P is the point of trisection of AB nearer A; Q is the mid-point of BC and R the point of trisection of DA nearer D.

Find the area of the triangle PQR

Posted in Math, asked by david, 6 years ago. 1899 hits.

## 1

Drawing a diagram, we can see the square ABCD is divided up into four shapes, APR,BQP, PQR and CDRQ.

So a simple way to work out the area of PQR is to work out the area of ABCD then take away the areas of the other shapes inside.

Area(ABCD)= length2 =62 = 36

Area(APR) = Base*Height/2 = 2*4/2 = 4

Area(BQP) = Base*Height/2 = 3*4/2 = 6

Area(CDRQ) = Height*(side+opposite side)/2 = 6*(3+2)/2 = 15

Therefore Area(PQR) = 36 - 4 - 6 - 15 = 11cm2

Russell Ludlow - 6 years ago
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