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Furqan Ali

PHYSICS

A rock is dropped from a high bridge. At the end of 3 seconds of free fall the speed of the rock is, in centimeters per second:

Posted in Physics, asked by Furqan Ali, 6 years ago. 4005 hits.

9

Given: Time = 3 secs

Now,

Velocity = Acceleration x Time.

As the rock is dropped from certain height that means gravity is working on it.

Therefore,

g = 9.8 m/s2 = 980 cm/s2

Hence,

V = g x t

   = 980 x 3

   = 2940 cm/s

Approx = 3000 cm/s

Gurudas Kadam
Gurudas Kadam - 6 years ago
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2

The rock is dropped from a high bridge.

Under free fall, rock is having acceleration due to gravity.

So acceleration of rock =9.8m/s^2

After 3 second, speed of rock = acceleration* time.

speed of rock = 9.8m/s^2*3 seconds = 29.4m/s = 2940cm/s.

vinu omanan
vinu omanan - 6 years ago
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