Log in

Connect faster with

Register

Signup faster with


|   Education without borders.
Menu
a Guest

sin(90+x)=?

Posted in Trigonometry, asked by ARCHU, 6 years ago. 2697 hits.

2

sin(90+x)

sin(A+B)=sinAcosB+cosAsinB

             =sin90cosx+cos90sinx

              =(1)cosx+(0)sinx

 sin(90+x)=cosx

Venkat Nagendra Thati
Venkat Nagendra Thati - 6 years ago
Ask Venkat Nagendra Thati for further help.
Report

0

sin(90+x)

Let 90= A and x=B. Then we have the above problem as

sin(A+B)=sinAcosB + cosAsinB

substituting original values we get the above equation as

Sin(90+x)=sin90cosx+cos90sinx

Now sin90=1 and cos90=0

thus the above equation becomes

Sin(90+x) = cosx + 0 = cosx

Anshula Basu
Anshula Basu - 6 years ago
Ask Anshula Basu for further help.
Report
Please register/login to answer this question. 
- Just now

0

a Guest
Just now
× Attachments/references, if any, will be shown after refreshing the page.
/homework-help
/homework-help/get_answer/297
/homework-help/save_reply/297
/homework-help/save_answer/297
/homework-help/accept_answer/297
/homework-help/unaccept_answer/297
/homework-help/unpublish_answer/297
/homework-help/delete_answer/297
/homework-help/update_answer/297
/homework-help/like/297
/homework-help/dislike/297
/homework-help/report_answer/297
/homework-help/report_question/297
/homework-help/save_bounty/297