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# algebra

the length of the three sides of a triangle are (x+1) cm, 2x cm and (3x+1) cm.  its perimeter is 30cm. find the value of x?

Posted in Math, asked by nikki, 6 years ago. 2065 hits.

## 0

given lengths of a triangle are AB=(x+1),BC=2x and CA=(3x+1)

perimeter of a triangle is given S=30 cm

perimeter of a triangle is, S=AB+BC+CA

30=x+1+2x+3x+1

30=6x+2

6x=28

x=14/3

Venkat Nagendra Thati - 6 years ago
Ask Venkat Nagendra Thati for further help.

## 0

GIVEN LENGTHS OF A TRIANGLE

AB = (x+1)

BC = 2x

CA = (3x+1)

PERIMETER OF A TRIANGLE IS GIVEN

S = 30 cm

PERIMETER OF A TRIANGLE

S = AB + BC + CA

30 = (x+1) + (2x) + (3x+1) [open brackets with the help of signs]

30 = x+1+2x+3x+1

30 = 6x+2

30 – 2 = 6x

28 =  6x

28/6 = x OR

X = 28/6   ( divided by 2 to make it simplest form )

X = 14/3

Furqan Ali - 6 years ago
Ask Furqan Ali for further help.
- Just now

## 0

Just now
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