algebra
the length of the three sides of a triangle are (x+1) cm, 2x cm and (3x+1) cm. its perimeter is 30cm. find the value of x?
Posted in Math, asked by nikki, 6 years ago. 2065 hits.
2 Answers
given lengths of a triangle are AB=(x+1),BC=2x and CA=(3x+1)
perimeter of a triangle is given S=30 cm
perimeter of a triangle is, S=AB+BC+CA
30=x+1+2x+3x+1
30=6x+2
6x=28
x=14/3
Venkat Nagendra Thati - 6 years ago
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GIVEN LENGTHS OF A TRIANGLE
AB = (x+1)
BC = 2x
CA = (3x+1)
PERIMETER OF A TRIANGLE IS GIVEN
S = 30 cm
PERIMETER OF A TRIANGLE
S = AB + BC + CA
30 = (x+1) + (2x) + (3x+1) [open brackets with the help of signs]
30 = x+1+2x+3x+1
30 = 6x+2
30 – 2 = 6x
28 = 6x
28/6 = x OR
X = 28/6 ( divided by 2 to make it simplest form )
X = 14/3
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