Connect faster with

Register

Signup faster with

|   Education without borders.

# by selling 45 lemons, a vendor loses a sum equal to the selling price of 3 lemons. find his loss per cent.

Posted in Math, asked by subham padhi, 6 years ago. 17412 hits.

## 113

Let X be the sellling price of one lemon

number of lemon = 45

so total selling price = 45X

loss = selling price of 3 lemon = 3X

So total cost = selling price + loss = 45X+3X =48X

Loss % = loss/total cost*100

= 3X/48X  *100

= 3/48 *100

= 100/16 = 6.25%

vinu omanan - 6 years ago
Ask vinu omanan for further help.

## 94

Let selling price of one lemon is x.

Selling price of 45 lemon = 45x

Loss= selling price of 3 lemon= 3x

Now Purchase price of lemon for vendor= Selling price+Loss=45x + 3x = 48x

hence % loss = (loss/purchase value)X100 = (3x/48x) X 100 = 6.25% ANSWER

Madhav Kishore - 6 years ago

## -73

Let the selling price of one lemon be= x

Therefore, the total Selling Price would be= 45x

Loss would be= 3x

Cost Price would be= selling price - loss

= 45x - 3x

= 42x

Therefore, loss%=(loss/cost price)×100

=(3x/42x)×100

=100/14

ANURAG BHUYAN - 6 years ago
Ask ANURAG BHUYAN for further help.
- Just now

## 0

Just now
× Attachments/references, if any, will be shown after refreshing the page.
/homework-help