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3x² - 16x + 13

Posted in Algebra, asked by Furqan Ali, 6 years ago. 1845 hits.

## 1

the power of the x is 2,so we will get the factors for this equation

when we calculate first term and last term of the equation, 39x2

we rewrite the product in the form of, -13x-3x

3x2-13x-3x+13=0

x(3x-13)-(3x-13)=0

(3x-13)(x-1)=0

=> x=13/3,x=1

Venkat Nagendra Thati - 6 years ago
Ask Venkat Nagendra Thati for further help.

## 1

SOL--- ,3x2-16x+13=0  . { 13*3 = 39 is the product and the sum is  -16 . so the factors are -13 and -3 , because -13*-3 =39 and (-13 ) + (-3) = (-16)  }

3x2-16x+13

3x2-13x-3x+13=0

x(3x-13)-1(3x-13)=0

(3x-13)(x-1)=0    => 3x-13 = 0 , x-1 = 0 => 3x=13 , x=1

x=13/3,x=1

amit helekar - 6 years ago
Ask amit helekar for further help.

## 0

3x2-16x+13

= 3x2-3x-13x+13  (Split 16x such that product of those numbers is 39 as a=3 and b=13 also see to it that sum of those number is the middle term i.e -16 in this case.)

= 3x(x-1) -13(x-1)

=(x-1)(3x-13)

therefore,

x-1=0 or 3x-13=0

x=1 or x =13/3

Roots are,

x=1 or x=4.33

Gurudas Kadam - 6 years ago
- Just now

## 0

Just now
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