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2 sin 40 cos10= sinA +sinB find A&B

Posted in English, asked by deepak gujar, 6 years ago. 2560 hits.

3

Sin(A+B)=SinA.CosB+CosA.SinB   ------1

Sin(A-B)=SinA.CosB-CoaA.SinB    -------2

Adding Eq1 and Eq2,

We get,  Sin(A+B)+Sin(A-B)=2SinA.CosB

Or,                2SinA.cosB=Sin(A+B)+Sin(A-B)   --------3

Given that, 2Sin40.Cos10=Sin(40+10)+Sin(40-10)      (As in Eq --3)

                                    =Sin50 + Sin30

                                    = SinA + SinB

Therefore, A=50° and B=30°

ANURAG BHUYAN
ANURAG BHUYAN - 6 years ago
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