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# a man has to reach a certain place at a certain time . if he walks 3km an hour ,he is 10 minutes late and if 4 km an hour he is 5 mins early. find the distance he has to walk?

Posted in Math, asked by sanjukta, 6 years ago. 4028 hits.

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distance he has to travel to reach the place=xkm

time given to reach the place=y minutes.

if he walk 3km in an hour he is 10 minutes late ie if he walks with a speed 3km/hour (3km/60min)he will take y+10 minutes

distance = time*speed

ie x=3/60km/minutes*(y+10)minutes

60x=3*(y+10)

20x=y+10

if he walks 4km in an hour he is 5minutes early ie if he walks with a speed of 4km/hour he will take y-5 minutes.

x=4/60km/minutes(y-5)minutes

60x=4(y-5)

15x=y-5

now we have two equations,

20x=y+10

15x=y-5

subtracting second equation from first,

5x=15

x=3km

vinu omanan - 6 years ago
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# a man has to reach a certain place at a certain time . if he walks 3km an hour ,he is 10 minutes late and if 4 km an hour he is 5 mins early. find the distance he has to walk?

Firstly, distance = speed*time

With the first speed we write: d = (3/60)*(t+10/60)

With the second speed we write: d = (4/60)*(t-5/60)

(4 km per hour=4 km/60mins)

Multiply both equations by 60:

1st: 60d=3(t+10)

2nd: 60d=4(t-5)

Put both equations equal to each other:

3(t+10)=4(t-5)

t=50 minutes

Substituting t back into both the first and second equation we get d=3 km.

Sofiane Saidoune - 6 years ago
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