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pravin

maths(word problem)

item b cost $1 more than item a.peter purchased 5 of item a and 6 of item b. the total expenditure is $32.60.what is the cost of item a and item b?

Posted in Math, asked by pravin, 6 years ago. 1922 hits.

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Let the price of item a=x.

So, price of item b=x+1

From the given condition 5a+6b=32.60

Plugging value of a and b.

5x+6(x+1)=32.60

5x+6x+6=32.60

11x+6=32.60

11x=32.60-6

11x=26.60

x=26.60/11=2.42

Cost of item a=$2.42 and cost of item b=$2.42+$1=$3.42

Madhukar  Gautam
Madhukar Gautam - 6 years ago
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item b cost $1 more than item a.peter purchased 5 of item a and 6 of item b. the total expenditure is $32.60.what is the cost of item a and item b?

Let cost of item a = $x

So, cost of item b = $(x+1)

Now,

5x+6(x+1)=32.60

5x+6x+6=32.60

11x=26.60

i.e. x=$2.42

Therefore cost of item a = $ 2.42

cost of item b = 2.42+1= $3.42

 

Neethu Nair
Neethu Nair - 2 years ago
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