Adrienne is twice as ols as rene.
a. Let Rene's age be represented by ____ years.
b. Then Adrienne's age is ____ years.
c. The sum of their ages 3 years ago was 48.
Please tell me how I should answer this or please just tell me the equation.....
Let rene age=x years.
So, Adrienne age=2x years.
3 years ago, Rene's age=x-3 years and Adrienne's age=2x-3
So, x-3+2x-3=48
3x-6=48
3x=54
x=18
Rene's age=18 years and Adrienne's age=36 years
Adrienne is twice as old as rene.
a. Let Rene's age be represented by ____ years.
b. Then Adrienne's age is ____ years.
c. The sum of their ages 3 years ago was 48.
The answer:
Rene=x years,
Means, Adrienne=2x years
3 years ago the sum of their age is 48
so...
(x-3)+(2x-3)=48
x+2x-3-3=48
3x-6=48
3x=48+6
3x=54
x=18
Rene=x=18
Adrienne=2x=18.2=36