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# Physics

The ball is thrown from a height of 2m at initial speed of 15 m/s and the starting direction forms a 35 degree angle.

a) What is the ball's flight time when it hits the ground?

b) maximum height of the ball?

c) air travel time?

Posted in Physics, asked by Thomas, 2 years ago. 671 hits.

## 0

a) Balls flight time when it hit the ground.

sin θ = vy / vi

vy = vi (sin θ)

vy = 15 m/s (sin 35°)

vy = 8.6 m/s

vf = vy - gt

0 = 8.6 m/s - (9.8 m/s2)(t1)

t1 = 0.88 s

hmax = 1/2 gt22

t2 = (2hmax / g)0.5

t2 = ((2 x 5.78 m) / 9.8 m/s2)0.5

t2 = 1.09 s

tT = t1 + t2

tT = 0.88 s + 1.09 s

tT = 1.96 s <--- Answer

b) Maximum height of the ball.

vf2 = vy2 - 2gh

0 = (8.6 m/s)2 - (2)(9.8 m/s2)h

(19.6 m/s2)h = 74.02 m2/s2

h = 3.78 m

hmax = 3.78 m + 2 m

hmax = 5.78 m <--- Answer

c) Air travel time.

tT = 1.96 s <--- Answer

John Philip Nadela - 4 months ago
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